(2x-5)(x^2+3x-1)=0

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Solution for (2x-5)(x^2+3x-1)=0 equation: 


Simplifying
(2x + -5)(x2 + 3x + -1) = 0

Reorder the terms:
(-5 + 2x)(x2 + 3x + -1) = 0

Reorder the terms:
(-5 + 2x)(-1 + 3x + x2) = 0

Multiply (-5 + 2x) * (-1 + 3x + x2)
(-5(-1 + 3x + x2) + 2x * (-1 + 3x + x2)) = 0
((-1 * -5 + 3x * -5 + x2 * -5) + 2x * (-1 + 3x + x2)) = 0
((5 + -15x + -5x2) + 2x * (-1 + 3x + x2)) = 0
(5 + -15x + -5x2 + (-1 * 2x + 3x * 2x + x2 * 2x)) = 0
(5 + -15x + -5x2 + (-2x + 6x2 + 2x3)) = 0

Reorder the terms:
(5 + -15x + -2x + -5x2 + 6x2 + 2x3) = 0

Combine like terms: -15x + -2x = -17x
(5 + -17x + -5x2 + 6x2 + 2x3) = 0

Combine like terms: -5x2 + 6x2 = 1x2
(5 + -17x + 1x2 + 2x3) = 0

Solving
5 + -17x + 1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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